Home
Blog
Contact
Mailing List
Software
 Blog
 Twitter
|
<< Back To All Blogs
Creating an MD5 String Extension method in C#
Wednesday, August 12th, 2009
Extension methods in C# allow for some very useful additions to the base .NET string library, and I recently came across the need to have an MD5 of a string, so I figured it would be very useful to add it as an extension method.
This allows for you to use a string, defined as follows:
string temp = "My string"
And obtain the MD5 of the string by executing the following:
string md5 = temp.MD5();
Without further ado, here is the code. Please note that this will only work in .NET 3.5 and above.
public static class StringExtensions
{
public static string MD5(this string input)
{
Encoder enc = System.Text.Encoding.Unicode.GetEncoder();
byte[] rawBytes = new byte[input.Length * 2];
enc.GetBytes(input.ToCharArray(), 0, input.Length, rawBytes, 0, true);
MD5 md5 = new MD5CryptoServiceProvider();
byte[] result = md5.ComputeHash(rawBytes);
StringBuilder sb = new StringBuilder();
for (int a = 0; a < result.Length; a++)
{
sb.Append(result[a].ToString("X2"));
}
return sb.ToString();
}
}
MD5in' Tom Out.
Tags
CSharp
Related Blogs
Good Ol Cross-Threaded Socket Action
Reading an XML file using LINQ
Comments
Tom said on Thursday, August 13th, 2009 @ 7:50 AM
Hi John,
Yes, you could easily do that by adding a parameter and changing the code around. In my particular case there was no need to use SHA-1 or a salted input, great idea though.
Tom
John Bubriski said on Thursday, August 13th, 2009 @ 7:40 AM
Since this is plain MD5 hashing, shouldn't you add a salt? Or maybe accept the salt as a parameter? Or you could change it to use SHA-1 for better reliability.
Tom said on Thursday, August 13th, 2009 @ 6:35 AM
@Joel,
That works as well, perhaps just old habits :)
Joel Lucsy said on Thursday, August 13th, 2009 @ 6:32 AM
Why not simply:
byte[] rawBytes = System.Text.Encoding.Unicode.GetBytes( input );
Add A Comment
Name:
URL:
Email Address: (not public, used to send notifications on further comments)
Comments:
Enter the text above, except for the 1st and last character:
|